So hot you Can't see It?
Most recent answer: 12/09/2014
- Anonymous
As you described, the peak wavelength emitted by a hot object (or any object above absolute zero) gets shorter as its temperature increases. This shift is described by , which says that the peak wavelength is inversely proportional to temperature. While the emission is strongest around the peak wavelength, in theory the object actually emits some light at all wavelengths, from x-rays to the infrared. The plot below shows some example thermal radiation spectra for different temperatures.
So, you asked whether it's possible to increase the temperature so much that all the light is emitted in wavelengths we can't see. As the temperature of an object increases, the amount of visible light that it radiates will actually always increase. As the temperature gets higher and the peak wavelength gets shorter, the object also just gets brighter—emitting more light at all wavelengths, including the visible part of the spectrum. You can see this in the plot: the lines representing higher temperatures are above the cooler ones over the whole range of wavelengths.
It took scientists a long time to figure out why these spectra have the shape they do. Classical theory why there's a peak in the spectrum, instead of just more and more energy at shorter wavelengths. Requiring light to be emitted and absorbed in discrete "packets" instead of a classical continuum turned out to solve the problem mathematically (although was thinking about a different problem when he first proposed this idea). It wasn't until even later that proposed that these mathematical quanta were real particles, what we now call photons.
Rebecca Holmes
(published on 12/09/2014)