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Q & A: Work done to move a charge on an equipotential surface

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Most recent answer: 12/11/2009
Q:
Why is the work done to move a charge on an equipotential surface Zero....
- Prudhvi Raj Borra (age 16)
Machilipatnam,Andhra,India.
A:
It's a matter of definition.  Equipotential means same potential everywhere.   The amount of work done on a charge Q when moving it from potential V1 to V2  is (V1 - V2 )*Q.   Since on an equipotential V1 is equal to V the net work is zero.

LeeH

(published on 12/11/2009)

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