Dispersion of Light
Most recent answer: 01/03/2015
- vignesh (age 15)
Chennai, Tamilnadu, India
That's a subtle question, not dumb at all!.
The light is not really absorbed and re-emitted in the usual sense of the words. That process would be called fluorescence. Fluorescence has a (somewhat random) time delay associated with it. Fluorescent light is emitted at lower frequency than the absorbed light, follows a different directional pattern, etc.
The interaction you're interested in here is scattering of the light. A classical picture of it works pretty well for most purposes. You can think of the electrons oscillating in response to the electric field of the light. These electrons then do emit light, at just the frequency of the incoming light (since that's the frequency of their response) and in a spatial pattern just matching that of the incoming beam. However, their emitted light is out of phase with the incoming beam, and this has the effect of slowing the propagation of the combined beam. Just as for a classical mass-on-spring oscillator, the amount and phase of the electron's response depends on their resonant frequency and on the driving frequency. (Here there are slight quantum corrections because there are multiple resonant frequencies corresponding to different energy levels.) It's the frequency dependence of the phase-delay and the amplitude of the scattered light that gives rise to the dispersion.
So this has a strong resemblance to what you were thinking, but not quite expressed in the absorption-emission framework. No single electron absorbs a whole photon in the scattering process. Each goes to a quantum state that is a superposition of the ground state and some (typically small) amplitude of excited states.
It's not always true that the higher frequencies see a bigger index of refraction, although that is typical for light in glass and many other familiar cases. Let's follow the reasoning for our classical picture. Typically, the main absorption lines (like classical resonances) are at frequencies higher than the visible light. That's like driving an oscillator at frequencies well below resonance, so the displacement depends mainly on the force (the electric field) and not on the frequency. Classical electromagnetism gives that the radiated field goes as the square of the oscillation frequency for fixed amplitude charge oscillations. So the scattering effect becomes stronger at higher frequencies.
Mike W.
(published on 01/03/2015)