Energy, Mass of Particles, and Speed
Most recent answer: 12/20/2013
- Tom Watkins (age 67)
Montpelier, VT, US
Hello Tom3,
The short answer to question #1 is zero.
The short answer to question #2 is infinity.
Okay, why?
The relativistic relationship of mass, energy, and momentum is E2 = m2c4 + p2c2 and the relativistic velocity addition relation is V2 = (V0+V1) /(1+V0V1/c2) where V1 if the initial velocity, and V0 is the is the velocity added in its own rest frame. If you plug in the value of c for the velocities of V0 or V1, the answer for V2 is still c. A particle with zero rest mass starts out with velocity c so adding energy to it can't possibly increase its speed. The increase in its frequency of oscillation accounts for the extra energy.
The speed is just c*sqrt(1-m2c4/E2) so you can add all the energy you want to a particle with finite rest mass but you can never quite reach a velocity of c.
LeeH
(published on 12/20/2013)
Follow-Up #1: Reaching the speed of light and emitting light
- Tom (age 67)
Montpelier, VT, US
Hi Tom,
Experiments have been done where more and more energy was pumped into electrons to see how fast they would go. Classically, you would expect them to keep speeding up, but relativistically, they just approach the speed of light asymptotically. They never reach c, because they have mass.
You can find more here: http://van.physics.illinois.edu/qa/listing.php?id=16708 or here: http://en.wikipedia.org/wiki/Tests_of_relativistic_energy_and_momentum.
As you near the speed of light, the amount of energy you need to apply to speed the particle up even a tiny bit explodes towards infinity.
2. Stars can't travel at the speed of light, so we can always see light which they emit. The redshift increases as the speed increases. I don't know of anything which can travel at the speed of light and still emit photons, so that kind of removes the craziness you may have been hoping for.
Cheers,
David Schmid
p.s. In the broad framework of a universe with accelerating expansion, a star which had once been visible can recede from us faster than c. However, it then becomes unobservable by any means. It's outside our cosmic horizon. Nothing it does has any effect here. /mw
(published on 12/22/2013)