Force due to an Accelerating Piston
Most recent answer: 10/27/2007
Q:
I am operating a large V-12 gasoline engine. The pistons weigh 8 pounds each, have a 6" bore and travel a 6.6" stroke. If the engine is running at 4,000 RPM, what are the computed G forces on the pistons as they reverse direction at the end of each stroke?
Thank you.
Ken Nott
Mach2@Rogers.com
- Ken Nott (age 56)
Oshawa, Ontario, Canada
Thank you.
Ken Nott
Mach2@Rogers.com
- Ken Nott (age 56)
Oshawa, Ontario, Canada
A:
f = 4000/60 = 66.67 Frequency in revolutions per second
w = f*2*pi = 418.9 Angular frequency in radians per second
x = 6.6*.0254 = 0.168 Stroke in meters
a = w^2*(x/2) = 14705 Acceleration in meters per sec^2
M = 8/2.2 = 3.64 Mass in kilograms
F = Ma = 50350 Force in Newtons
g = 9.8 Acceleration due to gravity
P = F*g/2.2 = 11319 Equivalent Force in pounds
That seems like a lot of force but if I haven’t made a mistake that’s what it comes out to.
LeeH
w = f*2*pi = 418.9 Angular frequency in radians per second
x = 6.6*.0254 = 0.168 Stroke in meters
a = w^2*(x/2) = 14705 Acceleration in meters per sec^2
M = 8/2.2 = 3.64 Mass in kilograms
F = Ma = 50350 Force in Newtons
g = 9.8 Acceleration due to gravity
P = F*g/2.2 = 11319 Equivalent Force in pounds
That seems like a lot of force but if I haven’t made a mistake that’s what it comes out to.
LeeH
(published on 10/27/2007)