# Time Dilation in a Mine

*Most recent answer: 11/18/2011*

Q:

I saw that gravitation time dilation is given by T=T0*sqrt(1-2GM/rc2) when outside of a non rotating sphere. what about inside? how do I compute time dilation at the bottom a mine?
thanks

- frederic reblewski (age 53)

saratoga, ca, usa

- frederic reblewski (age 53)

saratoga, ca, usa

A:

Let's start by remembering that the effects are pretty small, so that expression you gave can be accurately approximated as 1-GM/rc

To calculate the effect in a mine, you need some model for the density of the matter in the earth. Let's pick a really easy one, and say that the earth has uniform density. (Geologists could straighten us out on that.) Then integrating the field as one goes down gives a fractional slowdown of:

-(3/2)GM/Rc

Checks: this agrees with the other expression at the surface, where r=R. It also has the same slope there, which agrees with the gravitational field being a continuous function. So I'm confident it's ok.

Mike W.

^{2}. (Here G is the universal gravitational constant, M is the mass of the earth, c is the speed of light, and r r is the distance from the center of the earth. In other words, the fractional slow-down due to gravity near the earth, compared to far space, is -GM/rc^{2}. This expression only applies above the surface.To calculate the effect in a mine, you need some model for the density of the matter in the earth. Let's pick a really easy one, and say that the earth has uniform density. (Geologists could straighten us out on that.) Then integrating the field as one goes down gives a fractional slowdown of:

-(3/2)GM/Rc

^{2}+(1/2)GMr^{2}/R^{3}c^{2}where R is the radius of the earth.Checks: this agrees with the other expression at the surface, where r=R. It also has the same slope there, which agrees with the gravitational field being a continuous function. So I'm confident it's ok.

Mike W.

*(published on 11/18/2011)*