Levitating Mercury?
Most recent answer: 01/23/2008
- D.Weiss
Youngstown,Ohio
Mike W.
(published on 01/23/2008)
Follow-Up #1: levitating metals
- Bernard
Perth, Australia
If any conducting metal drops toward a strong magnetic field, eddy currents will be generated in the metal. The magnetic field of these currents will repel the magnetic field already there. However, the eddy currents are dissipated by resistance in the metal, allowing the metal to fall toward the magnet, just somewhat slowed.
Even if some turbulent liquid flow gets going in the liquid mercury, I don't see how it could be sustained without some additional energy source. So a mercury drop should fall, roughly similarly to other pieces of metal.
The previous question about mercury in sealed containers seemed to involve some old myth.
Mike W.
(published on 07/14/2009)
Follow-Up #2: diamagnetic levitation
- Nimish (age 17)
Mumbai, India
Typical metals are so weakly diamagnetic that you'd need a very strong field changing over a very short distance to provide enough force to levitate them in the Earth's gravitational field. That means working with a very small sample of the metal, not a large object. Still, it's possible in principle.
Some metals are not diamagnetic but rather weakly paramagnetic. Earnshaw's theorem proves that such paramagnetic material cannot be levitated by any combination of static fields. Such metals can be levitatedusing the eddy currents induced by ac fields, but that requires a steady energy input.
Very small animals (e.g. tiny frogs) can be levitated in dc fields thanks to their diamagnetism. The problems and the strength of the required fields become enormous for larger animals such as ourselves. Although I believe that people are not seriously hurt by the largest standard lab fields (say 15 Tesla) , those would not be nearly large enough to levitate anyone.
There's a nice discussion here: https://en.wikipedia.org/wiki/Diamagnetism.
Mike W.
(published on 07/18/2009)