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Hi, i'm very confused with my student's problem. He asked this question to me yesterday.
1. How to convert this unit : 2100 J/oC = .... Cal/K
2. 1 Kelvin is defined by : Unit of thermodynamic temperature, is the fraction 1/273.16 of the thermodynamic temperature of the triple point of water. His question is what is the triple point of water?
Thanks for your help
- Udin (age 30)
Surabaya, East Java, Indonesia
The triple point of water is 273.16 K, not far from 0°C. Your real units problems here are to convert K to °C and J to Cal. The first is easy: an increment of 1 K is the same exactly as an increment of 1°C. The second is standard: 1 J = (1/4.18) cal. So 2100J/°C=
2100 J/K= 502 cal/K.
(published on 07/09/08)
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