# Q & A: thermo units

## Learn more physics!

### Browse our 5920 answers by category Select a category About PhysicsAbout the VanAC...DCAir ResistanceAirplanesAnimals & PeopleAntimatterArchitectureBalanceBalloonsBaloney WebsitesBoiling, Evaporating & CondensingBouncing, Bumping & CrashingCareersChaosChargesChemistryCircuits & BatteriesColorsCompassesComputersConduction & ResistancecosmologyDensity & HardnessDiffraction & InterferenceDissolvingDistance, Velocity & AccelerationEarth & MoonEducationElectrocutionElectromagnetismElementary ParticlesEM WavesEntropyExplosionsFireFrictionGetting to SpaceGizmos & GadgetsGlowingGravityGreen EnergyHard to CategorizeHealthHistoryHomemade BatteriesHomemade RocketsInside the AtomIt Floats!LasersLenses & MirrorsLiquid FlowMaglevMagnetsMathMeasurementsMelting & FreezingMicrowave OvensMusicNewton's LawsNon-Newtonian FluidsOscillations & ResonancePhilosophyPlantsPressureProperties of LightProperties of SoundProperties of WaterQuantum MechanicsRadioactivityReally Really Really ColdRelativityRustingSaving the WorldScience ProjectsScientific InstrumentsShadowsSimple MachinesSky & AirSpeed of SoundSportsStates of MatterStuff that SparksStuff that SpinsSun & StarsSuperconductivitySurface TensionTelescopes, Binoculars & CamerasTemperature & HeatThe ElementsThe Rest of the Solar SystemThe Rest of the UniverseThe WebsiteTidesTimeTo Be Discovered...Types of EnergyVacuumVan DemosWater WavesWhat Atoms Look LikeWork, Energy & Momentum or search term

Q:
Hi, i'm very confused with my student's problem. He asked this question to me yesterday. 1. How to convert this unit : 2100 J/oC = .... Cal/K 2. 1 Kelvin is defined by : Unit of thermodynamic temperature, is the fraction 1/273.16 of the thermodynamic temperature of the triple point of water. His question is what is the triple point of water? Thanks for your help Udin
- Udin (age 30)
Surabaya, East Java, Indonesia
A:
The triple point of water is 273.16 K, not far from 0°C. Your real units problems here are to convert K to °C and J to Cal. The first is easy: an increment of 1 K is the same exactly as an increment of 1°C. The second is standard: 1 J = (1/4.18) cal. So 2100J/°C=
2100 J/K= 502 cal/K.

Mike W.

(published on 07/08/2008)